Math, asked by amuammu61297, 4 months ago

1. 2y2 - 21y +55 = 0 solve by using quadratic equation ​

Answers

Answered by kumarrohit248624
0

2y^2 - 21y + 55 = 0

2y^2 - 10y - 11y + 55 = 0

2y ( y - 5) - 11 ( y - 5) = 0

(2y -11) (y - 5) = 0

either y = 11/2 or y = 5

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