(1,3)(0,2)(-4,0) are they collinear
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Answer:
Let the three points be A(1,3), B(0,2) and C(-4,0).
Now, for A, B and C to be collinear, it should satisfy AB+BC=AC
Now find
AB=√1²+1²=√2
BC=√4²+2²=√20
AC=√3²+3²=√18
Here, I have used distance formula.
Now let's see if AB+BC=AC
√2+√20=√2(1+√10)
And √18=3√2
Hence, AB+BC≠AC
so They are non-collinear
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Another method:
Slope from (1,3) to (0,2) is (3-2) / (1–0) = 1/1= 1
Slope from (0,2) to (-4,0) is 2/4= 1/2
Hence,both slopes are not equal,so they are not collinear.
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