Question

1/3^-1 - 1/4^-1^-1
plss this is urgent

Answer 1

Given that,

$[(\frac{1}{3} )^{-1} - (\frac{1}{4} )^{-1} ]^{-1}$

As we know that,

$(\frac{x}{y} )^{-1}= \frac{y}{x}....(1)$

The same rule we have to apply here, so we get

$[(\frac{1}{3} )^{-1} - (\frac{1}{4} )^{-1} ]^{-1}=[(\frac{3}{1} ) - (\frac{4}{1})]^{-1}$

$=[3-4]^{-1}$

Now according to BODMAS rule first we have to solve bracket and then order, so we get

$[(\frac{1}{3} )^{-1} - (\frac{1}{4} )^{-1} ]^{-1}=(\frac{-1}{1} )^{-1}$

Now according to equation (1),

$[(\frac{1}{3} )^{-1} - (\frac{1}{4} )^{-1} ]^{-1}=(\frac{1}{-1} )$

So the correct answer for the given question is

$[(\frac{1}{3} )^{-1} - (\frac{1}{4} )^{-1} ]^{-1}= (-1)$