Question

1-√3÷1+√3=a+b find a & b ​

Answer 1

$\huge{\mathcal{\green{Answer}}}$

$\frac{1 - \sqrt{3} }{1 + \sqrt{3} } = a + b \\ \frac{1 - \sqrt{3} }{1 + \sqrt{3} } \times \frac{1 - \sqrt{3} }{1 - \sqrt{3} } = a + b \\ \frac{1 - \sqrt{3 } - \sqrt{3} + 3 }{(1) { }^{2} - ( \sqrt{3}) {}^{2} } = a + b \\ \frac{4 - 2 \sqrt{3} }{1 - 3} = a + b \\ \frac{4 - 2 \sqrt{3} }{ - 2} = a + b \\ \frac{4}{ - 2} + ( \frac{ - 2 \sqrt{3} }{ - 2} ) = a + b \\ ............................ \\ a = \frac{4}{ - 2} ........b = ( \frac{ - 2 \sqrt{3} }{ - 2}$

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