Question

[(1/3)^-2÷(1/9)^-1]×1/27
Anwer

Answer 1

hey mate

here goes ur answer

$= (( { \frac{1}{3} }^{ - 2} ) \div ( { \frac{1}{9} }^{ - 1} ) \times \frac{1}{27} \\ = ( {3}^{2} \div {9}^{ 1} ) \times \frac{1}{27} \\ = {3}^{2 - 2} \times {3}^{ - 3}={3}^{0-3}={3}^{-3} \\ = \frac{1}{27}$

hope it helps u