Question

[(1/3)-² +(2/3)-³ +(1/2)-¹]0​

Answer 1

(1/2)-³+(1/3)-²+(1/4)-¹

= (2)3 + (3)2 + (4) 1

= 8 + 9 + 4

= 21

Answer 2

Answer:

1. If your question is:

[ (1/3$)^{-2}$ +(2/3$)^{-3}$ +(1/2$)^{-1}$$]^{0}$

Solution = 1

Identity: [$a^{0} = 1$]                                    [ Where a is any number.]

2. However,

If your question is :

[(1/3$)^{-2}$ +(2/3$)^{-3}$ +(1/2$)^{-1}$] × 0

Solution = 0

a × 0 = 0                                             [ Any number multiplied by 0 = 0 ]

Hope you got both the answers.

Thank you.