Math, asked by seeyanasamreen, 6 months ago

1/3✓2-2✓3 please answer fast​

Answers

Answered by mysticd
1

 Given \: \frac{1}{(3\sqrt{2} - 2\sqrt{3})}

 = \frac{(3\sqrt{2} + 2\sqrt{3})}{(3\sqrt{2} - 2\sqrt{3})(3\sqrt{2} + 2\sqrt{3})}

 = \frac{(3\sqrt{2} + 2\sqrt{3})}{(3\sqrt{2})^{2}- (2\sqrt{3})^{2}}

 = \frac{(3\sqrt{2} + 2\sqrt{3})}{18 - 12}

 = \frac{(3\sqrt{2} + 2\sqrt{3})}{6}

 = \frac{(3\sqrt{2}}{6} + \frac{2\sqrt{3})}{6}

 = \frac{\sqrt{2}}{2} + \frac{\sqrt{3}}{3}

Therefore.,

 \red{ \frac{1}{(3\sqrt{2} - 2\sqrt{3})}}

 \green {= \frac{\sqrt{2}}{2} + \frac{\sqrt{3}}{3}}

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