Question

(1/√3+√2)-(2/√5-√3)-(3/√2-√5)​

Answer 1

PLEASE MARK AS BRAINLIEST

Answer 2

Answer:

Step-by-step explanation:

(1/√3+√2)-(2/√5-√3)-(3/√2-√5)

=(1/√3)+√2-(2/√5)+√3-(3/√2)+√5

(multiply denominator and numerator by the root in the denominator

eg- 2/√3 = 2*√3/√3*√3 = 2√3/3 )

=(√3/3)+√2-(2√5/5)+√3-(3√2/2)+√5              

take LCM

=(10√3 + 30√2 - 12√5 + 30√3 - 45√2 + 30√5) / 30

=(30√3 - 15√2 + 18√5) / 30

= √3 -(√2/2) + (3√5/5)