1/√3+√2-2/√5-√3-3/√2-√5
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Hello mate!
1/ ( √3 + √2 ) = 1/( √3 + √2 ) × ( √3 - √2 )/( √3 - √2 )
= ( √3 - √2 )/( 3 - 2 ) = √3 - √2
2/( √5 - √3 ) =
2/( √5 - √3 ) × ( √5 + √3 )/( √5 + √3 )
= 2( √5 + √3 )/ ( 5 - 3 ) = √5 + √3
3/( √2 - √5 ) =
3/( √2 - √5 ) × ( √2 + √5 )/( √2 + √5 )
= 3( √2 + √5 )/( 2 - 5 ) = - √2 - √5
√3 - √2 - ( √5 + √3 ) - ( - √2 - √5 )
= √3 - √2 - √5 - √3 + √2 + √5
= 0
Hope it helps
1/ ( √3 + √2 ) = 1/( √3 + √2 ) × ( √3 - √2 )/( √3 - √2 )
= ( √3 - √2 )/( 3 - 2 ) = √3 - √2
2/( √5 - √3 ) =
2/( √5 - √3 ) × ( √5 + √3 )/( √5 + √3 )
= 2( √5 + √3 )/ ( 5 - 3 ) = √5 + √3
3/( √2 - √5 ) =
3/( √2 - √5 ) × ( √2 + √5 )/( √2 + √5 )
= 3( √2 + √5 )/( 2 - 5 ) = - √2 - √5
√3 - √2 - ( √5 + √3 ) - ( - √2 - √5 )
= √3 - √2 - √5 - √3 + √2 + √5
= 0
Hope it helps
divyanshu441:
thanks
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