Question

-1/3,-2/9,-4/3 Write the following rational numbers in ascending order

Answer 1

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Answer 2

Step-by-step explanation:

Given:

$\frac{-1}{3}, \frac{-2}{9},\frac{-4}{3}$

To find:

Given rational numbers in ascending order.

Solution:

• To solve this question, let us take the L.C.M of the class of rational numbers or convert them into fractions like them.  

• After the conversion, the numbers can be easily arranged by comparison.

Given that,

⇒ $\frac{-1}{3}, \frac{-2}{9},\frac{-4}{3}$

The L.C.M of $3,9$ and $3$ is $9.$

Therefore,

⇒ $\frac{-1}{3}$

Now, multiply $3$ by both denominator and numerator,

⇒ $\frac{-3}{9}$

and the next term,

⇒  $\frac{-4}{3}$

Here also multiply $3$ by both denominator and numerator,

⇒ $\frac{-12}{9}$

The term $\frac{-2}{9}$ has the denominator $9$. So, it is not necessary for further conversion.

⇒ $\frac{-2}{9}$

Now arranging them into ascending order we get,

⇒ $\frac{-12}{9} < \frac{-3}{9} <\frac{-2}{9}$  

or,

⇒ $\frac{-4}{3} < \frac{-1}{3} <\frac{-2}{9}$

Hence the answer is $\frac{-4}{3} < \frac{-1}{3} <\frac{-2}{9}.$

Answer:

The ascending order of the given rational numbers $\frac{-1}{3}, \frac{-2}{9},\frac{-4}{3}$ is $\frac{-4}{3} < \frac{-1}{3} <\frac{-2}{9}.$