Question

1
______
√3+√2

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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$\frac{1}{ \sqrt{3} + \sqrt{2} } \\ = \frac{1}{ \sqrt{3} + \sqrt{2 } } \times \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \\ = \frac{ \sqrt{3} - \sqrt{2} }{ { \sqrt{3} }^{2} - { \sqrt{2} }^{2} } \\ = \frac{ \sqrt{3} - \sqrt{2} }{3 - 2} \\ = \sqrt{3} - \sqrt{2}$

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