Question

1/√3-√2 rationalize...... ​

Answer 1

Answer:

$$\begin{lgathered}\frac{ \sqrt{3} + \sqrt{2} }{( \sqrt{3} - \sqrt{2})( \sqrt{3} + \sqrt{2} } \\ = \frac{ \sqrt{3} + \sqrt{2} }{3 - 1} \\ = \sqrt{3} + \sqrt{2} \: \: ans\end{lgathered}$$

Answer 2

Answer:-

$= \frac{1}{ \sqrt{3} - \sqrt{2} } \\ \\ = \frac{1}{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} }$

$= \frac{ \sqrt{3} + \sqrt{2} }{3 - 2}$

$= \frac{ \sqrt{3} + \sqrt{2} }{1}$

$= \sqrt{3} + \sqrt{2}$