Question

1/3(2x-1)-1/4(2x+1)=1/12(2-x)​

Answer 1

Given:

1/3(2x-1)-1/4(2x+1)=1/12(2-x)​

To find:

1/3(2x-1)-1/4(2x+1)=1/12(2-x)​

Solution:

From given, we have,

1/3(2x-1) - 1/4(2x+1) = 1/12(2-x)​

2x/3 - 1/3 - 2x/4 - 1/4 = 2/12 - x/12

2x/3 - 1/3 - x/2 - 1/4 = 1/6 - x/12

2x/3 - x/2 + x/12 = 1/6 + 1/4 + 1/3

x (2/3 - 1/2 + 1/12) = 1/6 + 1/4 + 1/3

solving the above fractions, we get,

x (8/12 - 6/12 + 1/12) = 2/12 + 3/12 + 4/12

x [(8 - 6 + 1)/12] = (2 + 3 + 4)/12

x (8 - 6 + 1) = 2 + 3 + 4

x (3) = 9

x = 3

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Value\:of\:x=3}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies \frac{1}{3} (2x - 1) - \frac{1}{4}(2x + 1) = \frac{1}{12} (2 - x) \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies value \: of \: x = ?$

• According to given question :

$\tt:\implies \frac{1}{3} \times (2x - 1) - \frac{1}{4} \times (2x + 1) = \frac{1}{12} \times (2 - x)\\ \\ \tt:\implies \frac{2x - 1}{3} - \frac{2x + 1}{4} = \frac{2 - x}{12} \\\\ \tt:\implies \frac{8x - 4 - (6x + 3)}{12} = \frac{2 - x}{12} \\\\ \tt:\implies \frac{8x - 4 - 6x - 3} {12} \times 12 = 2 - x \\\\ \tt:\implies 2x - 7 = 2 - x \\\\ \tt:\implies 2x + x = 2 + 7 \\\\\ \tt:\implies 3x = 9 \\\\ \tt:\implies x = \frac{9}{3} \\\\\ \green{\tt:\implies x = 3}$