Math, asked by MoupriyaMondal, 1 year ago

{(1/3)^-3-(1/2)^-3}÷(1/4)^-3​

Answers

Answered by Anonymous
5

Answer:

 \frac{19}{64}

Step-by-step explanation:

 =  >  \frac{( { \frac{1}{3}) }^{ - 3} -  ({ \frac{1}{2} })^{ - 3}  }{ ({ \frac{1}{4} })^{ - 3}  } \\  \\  =  >  \frac{ {3}^{3}  -  {2}^{3} }{ {4}^{3} }   \:  \:  \:  \because \:  \: ( { \frac{1}{x}})^{ - n}  =  {x}^{n}  \\  \\  =  >  \frac{27 - 8}{64}  \\  \\  =  >  \frac{19}{64}

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