Question

[(1/3)^-3-(1/2)^-3]/(1/4)^-3

Answer 1

Answer:

The answer is $\frac{19}{64}$

Step-by-step explanation:

     $\frac{(\frac{1}{3})^{-3}-(\frac{1}{2})^{-3}}{(\frac{1}{4})^{-3}}$

$=\frac{(3^{-1})^{-3}-(2^{-1})^{-3}}{(4^{-1})^{-3}}$, since $\frac{1}{a}=a^{-1}$

$=\frac{3^3-2^3}{4^{3}}$, since $(a^m)^n=a^{mn}$

$=\frac{27-8}{64}=\frac{19}{64}$