{(1/3)^-3-(1/2) ^-3}÷(1/4) ^-3
plz solve it!!!!
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Answer:
Step-by-step explanation:
[(1/3)⁻³ - (1/2)⁻³] / (1/4)⁻³
We know the exponents rule a⁻ⁿ = 1/aⁿ
Thus
(1/3)⁻³ = 1/ (1/3)³ = (3)³ = 27
(1/2)⁻³ = 1/ (1/2)³ = (2)³ = 8
(1/4)⁻³ = 1/(1/4)³ = (4)³ = 64.
Now substitute the values back in the given sum:
[(1/3)⁻³ - (1/2)⁻³] / (1/4)⁻³
= 27 - 8 / 64
= 19/64.
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