Question

{(1/3)^-3-(1/2) ^-3}÷(1/4) ^-3


plz solve it!!!!
its urgent.​

Answer 1

Answer:

Step-by-step explanation:

[(1/3)⁻³ - (1/2)⁻³] / (1/4)⁻³

We know the exponents rule a⁻ⁿ = 1/aⁿ

Thus

(1/3)⁻³ = 1/ (1/3)³ =  (3)³ = 27

(1/2)⁻³ = 1/ (1/2)³ = (2)³ = 8

(1/4)⁻³ = 1/(1/4)³ = (4)³ = 64.

Now substitute the values back in the given sum:

[(1/3)⁻³ - (1/2)⁻³] / (1/4)⁻³

= 27 - 8 / 64

= 19/64.