1+√3+3+3√3+.....To 10 terms
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If you observe the terms of this question are in G.P. with first term as 1 and common ratio as √3/1 =√3 .
Sum of n terms in a G.P. = a(1-r^(n+1)/(1-r) . So sum of 10 terms in this G.P. =1(1-√3^11)/(1-√3) =
1-243√3/1-√3 = (1-243√3)(1+√3)/(1-√3)(1+√3) = 1-243√3+√3-729/ 1-3 => -728-242√3/(-2) => 364+121√3 .Hope it helps you... Mark me as Brainliest if you think i am worthy of it.
Sum of n terms in a G.P. = a(1-r^(n+1)/(1-r) . So sum of 10 terms in this G.P. =1(1-√3^11)/(1-√3) =
1-243√3/1-√3 = (1-243√3)(1+√3)/(1-√3)(1+√3) = 1-243√3+√3-729/ 1-3 => -728-242√3/(-2) => 364+121√3 .Hope it helps you... Mark me as Brainliest if you think i am worthy of it.
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