Question

1/3,3/7,2/5 arrange them in ascending order

Answer 1

Answer:

1. Arrange the following fractions 5/6, 8/9, 2/3 in ascending order.

First we find the L.C.M. of the denominators of the fractions to make the denominators same.

L.C.M. = 3 × 2 × 3 × 1 = 18

Now to make the fraction as like fractions divide the L.C.M. by the denominator of fractions, then multiply both the numerator and denominator of fraction with the number get after dividing L.C.M.

As in fraction 5/6 denominator is 6.

Divide 18 ÷ 6 = 3

Now, multiply both numerator and denominator by 3 = 5 × 3/6 × 3 = 15/18

Similarly, 8/9 = 8 × 2/9 × 2 = 16/18 (because 18 ÷ 9 = 2)

and 2/3 = 2 × 6/3 × 6 = 12/18 (because 18 ÷ 3 = 6)

Now, we compare the like fractions 15/18, 16/18 and 12/18

Comparing numerators, we find that 16 > 15 > 12

Therefore, 16/18 > 15/18 > 12/ 18

or 8/9 > 5/6 > 2/3

or 2/3 < 5/6 < 8/9

The ascending order of the fractions is 2/3, 5/6, 8/9.

2. Arrange the following fractions 1/2, 3/8, 2/3, 4/5 in ascending order.

First we find the L.C.M. of the denominators of the fractions to make the denominators same.

L.C.M. of 2, 8, 3 and 5 = 120

Now to make the fraction as like fractions divide the L.C.M. by the denominator of fractions, then multiply both the numerator and denominator of fraction with the number get after dividing L.C.M.

As in fraction 1/2 denominator is 2.

Divide 120 ÷ 2 = 60

Now, multiply both numerator and denominator by 60 = 1 × 60/2 × 60 = 60/120

Similarly, 3/8 = 3 × 15/8 × 15 = 45/120 (because 120 ÷ 8 = 15)

Answer 2

Given,

$\[\frac{1}{3},\frac{3}{7},\frac{2}{5}\]$

Solution,

Arrange fractions in ascending order.

$\[ = \frac{1}{3} \times \left( {3 \times 7 \times 5} \right),\frac{3}{7} \times \left( {3 \times 7 \times 5} \right),\frac{2}{5} \times \left( {3 \times 7 \times 5} \right)\]$

$\[ = 1 \times \left( {7 \times 5} \right),3 \times \left( {3 \times 5} \right),2 \times \left( {3 \times 7} \right)\]$

$\[ = 35,45,42\]$

$\[ = 35 < 42 < 45\]$

Observe the given fraction.

$\[\frac{1}{3} < \frac{2}{5} < \frac{3}{7}\]$

Hence the ascending order is $\[\frac{1}{3} < \frac{2}{5} < \frac{3}{7}\]$