Question

(-1/3)^-3 x( 1/9)^ 2 ÷(3)^-1​

Answer 1

Answer:

-1 is your answer

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Answer 2

$\bold{ - { \frac { 1} {3} }^{ - 3} \times { \frac{1}{9} }^{2} \div {3}^{ - 1} }$

we know that,

$\bold{{ (\frac{a}{b}) }^{ - 2} \: = \: { (\frac{b}{a} )}^{2} } \\ \bold{therefore,} \\ \bold{ = \: { ( - \frac {3}{1}) }^{ 2} \times { (\frac{1}{9}) }^{2} \div ( { \frac{1}{3}) }^{1} } \\ \bold{ = \: { ( - \frac{3}{1}) }^{2} \times { (\frac{1}{9}) }^{2} \times \frac{3}{1} } \\ \bold{ = \: \frac{ - 3 \times - 3 \times 1 \times 1 \times 3}{1 \times 9 \times 1} } \\ \bold{ = \: \frac{ - \cancel 3 \times - \cancel3 \times 1 \times 1 \times 3}{1 \times \cancel9 \times 1} } \\ \bold \red{ = \: 3 \: \: \: \: \: \: \: \: \: \: ....ans}$

hope it helps you..

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