(1/3+3i)(1/3+3i)(1/3+3i)
Answers
Answer: PLEASE BRAINLIEST MY ANSWER
Step-by-step explanation:
Q) (1/3+3i)(1/3+3i)(1/3+3i)
⇒ (1/3+3i)(1/3+3i)(1/3+3i) = (1/3+3i)³ ----[we know (a+b)³ = a³+3a²b+3ab²+b³]
= (1/3)³ + 3×(1/3)²×(3i) + 3×(1/3)×(3i)² + (3i)³
= (1/27) + (9i/9) + (27i²/3) + 27i³
= (1/27) + 1i + 9i² + (27×i²×i)
= (1/27) + 1i + 9×(-1) + 27i×(-1)
= (1/27) + 1i -9 - 27i
= [(1/27) - 9] + [1i - 27i]
= [(1 - 9×27) / 27] - 26i
= [(1 + 243) / 27] - 26i
= (244/27) - 26i