Question

1+3=4 0+3=0 2+4=12 5+4=45 3+5=?

Answer 1

1+3=4 =>1+3=4 => 4×1=4
0+3=0 => 0+3=3 => 3×0=0
2+4=12 =>2+4= 6 => 6×2=12
5+4=45 => 5+4=9 => 9×5=45
3+5= 24=> 3+5=8 => 8×3=24

Answer 2

Answer:

The missing value is 24.

Step-by-step explanation:

From the given equations it is noticed that if

$a+b=c$

then,

$c=a\times (a+b)$

$1+3=4$

$1\times (1+3)=1\times 4=4$

$0+3=0$

$0\times (0+3)=0\times 3=0$

$2+4=12$

$2\times (2+4)=2\times 6=12$

$5+4=45$

$5\times (5+4)=5\times 9=45$

$3+5=?$

$3\times (3+5)=3\times 8=24$

Therefore the missing value is 24.