Question

(1-3)/4+(1-1)/5-01-2)/3=1 please can anyone tell me the correct answer of this math question. ​

Answer 1

Answer:

$\frac { \frac { 1 - 3 } { 4 } + \frac { 1 - 1 } { 5 } - 1 - 2 } { 3 } \\ \frac{\frac{-2}{4}+\frac{1-1}{5}-1-2}{3} \\ \frac{-\frac{1}{2}+\frac{1-1}{5}-1-2}{3} \\ \frac{-\frac{1}{2}+\frac{0}{5}-1-2}{3} \\ \frac{-\frac{1}{2}-1-2}{3} \\ \frac{\frac{-1-2}{2}-2}{3} \\ \frac{-\frac{3}{2}-\frac{4}{2}}{3} \\ \frac{-\frac{7}{2}}{3} \\ \frac{-7}{2\times 3} \\ -\frac{7}{6} \\ -\frac{7}{6}\approx -1.166666667$

−1.16666666 is not equal to 1 so the statement is false

mark me brainliest i need for my rank

follow ❤️

Answer 2

Step-by-step explanation:

Answer:

\begin{gathered}\frac { \frac { 1 - 3 } { 4 } + \frac { 1 - 1 } { 5 } - 1 - 2 } { 3 } \\ \frac{\frac{-2}{4}+\frac{1-1}{5}-1-2}{3} \\ \frac{-\frac{1}{2}+\frac{1-1}{5}-1-2}{3} \\ \frac{-\frac{1}{2}+\frac{0}{5}-1-2}{3} \\ \frac{-\frac{1}{2}-1-2}{3} \\ \frac{\frac{-1-2}{2}-2}{3} \\ \frac{-\frac{3}{2}-\frac{4}{2}}{3} \\ \frac{-\frac{7}{2}}{3} \\ \frac{-7}{2\times 3} \\ -\frac{7}{6} \\ -\frac{7}{6}\approx -1.166666667\end{gathered}

3

4

1−3

+

5

1−1

−1−2

3

4

−2

+

5

1−1

−1−2

3

−

2

1

+

5

1−1

−1−2

3

−

2

1

+

5

0

−1−2

3

−

2

1

−1−2

3

2

−1−2

−2

3

−

2

3

−

2

4

3

−

2

7

2×3

−7

−

6

7

−

6

7

≈−1.166666667