1+3+5+. +199, then the sum of AP is a)10000 b) 10,500 e) 11,000 D) 10,8006
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PLS MARK BRAINLIEST & ♥️⭐⭐⭐⭐⭐
Step-by-step explanation:
AP is 1,3,5,7....199
a=1,d=2 and last term l=199
tn=a+(n−1)d⇒199=1+(n−1)×2⇒2n=200n=100∴sum=2n[a+l]=2100[1+199]=2100×200=10000
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Answer:
AP is 1,3,5,7 .... 199 a = 1 , d = 2 and last term I = 199 tn = a + ( n - 1 ) d 199 = 1 + ( n - 1 ) * 2 2n = 200 n = 100 sum = n2 [ a + 1 ] = 1002 [ 1 + 199 ] = 1002 ...
Step-by-step explanation:
I hope I helped you
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