1+3+5+….+(2n-1)= say the answer
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Answered by
0
Answer:
11 n ooooooooooook
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Answered by
0
Answer:
The result is true for n = 1, since
n2=12=1
Let the result be true for n= k, that is
1+3+5+⋯+(2k−1)=k2
we need to prove that the result is also true for n = k + 1, that is
1+3+5+⋯+(2k−1)+(2k+1)=(k+1)2
by our assumption
1+3+5+⋯+(2k−1)=k2
adding 2 k + 1 on both sides
1+3+5+⋯+(2k−1)+(2k+1)=k2+(2k+1)=(k+1)2
∴The result is true for n = k + 1. Hence by the principle of mathematical
induction, the result is true for all n∈Z+
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