Question

1.3.5 +3.5.7 +5.7.9+...
find sum of n terms
ans will be n(n+1)(2n²+4n-1)
show the process​

Answer 1

Answer:

Tñ = (2n-1)(2n+1)(2n+3) = (4n²-1)(2n+3) = 8n³ + 12n² -2n - 3

Tn = 8n³ + 12n² -2n - 3

now use summation formula of n³ , n², n & constant.