1+3+5+7+9+11+13+15...... के 15 पदों तक का योगफल कितना होगा
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Answer:-
Given:
1 , 3 , 5..... are in AP.
Hence,
- a (first term) = 1
- d (common difference) = 3 - 1 = 2
We know that,
Sum of first n terms of an AP (Sn) = n/2 * [2a + (n - 1)d]
Hence,
→ S(15) = (15/2) * [ 2(1) + (15 - 1)(2) ]
→ S(15) = 15/2 * (2 + 28)
→ S(15) = 15/2 * 30
→ S(15) = 225
Hence, the sum of first 15 terms of the given series is 225.
Additional Information:-
- A series in which each term (except first term) differs from its preceding term by a fixed quantity is called an Arithmetic Progression (AP).
- The fixed quantity is called common difference.
- General form of an AP is a , a + d .... if a is the first term and d is the common difference.
- nth term of an AP is a + (n - 1)d.
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Explanation:
1+3+5+7+9+11+13+15...... के 15 पदों तक का योगफल कितना होगा
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