Question

1,3,5,7,9,11,13,15 kaun also boox 3 answar
30

Answer 1

Answer:

This is not possible. If you take the numbers to be modulo 2, five odd numbers would sum up to 1, but 30 is 0 modulo 2

WHY:-

1.3.5.7.9.11,13 and 15 is

Now

we can say that the number we have to prove

x+y+z=30

for all x,y,z ∈ 2n+1 where n∈N(Natural numbers).

now, let 3 value of n is a, b and c then

LHS is

=x+y+z

=2a+1+2b+1+2c+1

2(a+b+c)+3

2m+3 where m =(a+b+c)

by equating with RHS we get

2m+3=30

2m=27

now m=a+b+c

and a,b ∈N.

therefore a,b,c is a Natural number⇒m is a Natural number.

Now for any natural number 'm' we can`t get 2m=30.

Answer 2

Answer:

heya refer to the attachment