1+3+5+7+9+11+13+15+.... what would the sum of first 15th terms of the series?
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Answered by
0
Answer:
answer is 345...........
Answered by
0
Step-by-step explanation:
a=t1 =1
t2=3
d=2
n=15
Sn=?
Sn=n/2[2a+(n-1)d]
=15/2 [2+14×2]
=15×28
=420
S15 = 420
420 is your answer
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