Question

1 + 3 + 5 + 7 + 9 + so on+ n is equal to what​

Answer 1

Step-by-step explanation:

1 + 3 + 5 + ... + n terms

The sequence 1 , 3 , 5 ... is an A. P.

with a = 1 and d = 2

sum of n terms

$sn = \frac{n}{2} (2a + (n - 1)d) \\ \\ \\ = \frac{n}{2} (2 + 2n - 2) \\ \\ \\ = n.n \\ \\ \\ = {n}^{2}$

1 + 3 + 5 ... n terms = n^2

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