1+3+5+7+.....sum of first 25odd positive integers is
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6
Answer:
1+3+5+7+9+11+13+15+17+19+21+23+25+27+29+31+33+35+37+39+41+43+45+47+49 = 625
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Answered by
31
a = first term = 1
d = 3 -1 = 2
n = number of terms = 25
than , according to A.P 's formula
an = a + {n-1} × d
an = 1+ { 25-1} × 2
an = 49
first 25 ood positive number till 49
sn = n/2 ×{ a + an}
sn = 25/2 ×{1+49}
sn = 25× 25 = 625 answer..
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