1;3;5;7......to100 terms ,200 terms find the sum of arithmetic series
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Step-by-step explanation:
1,3,5,7,.... are in ap
difference = 3 - 1 = 2
arithmetic mean = n/2(2a + (n - 1)d)
for 200 terms,
200/2(2(1) + 199(2))
= 100( 2 + 398 )
= 100(400)
= 40000
for 100 terms
arithmetic mean = n/2(2a + (n - 1)d)
= 100/2(2(1) + (99)2)
= 50(2 + 198 )
= 50(200)
= 10000
Hope this is helpful to you
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