Question

(1+3+5+...+99)/(2+4+6+...+100)

Answer 1

Answer:

numerator=1+3+5.......99

an=a+(n-1)d

99=1+(n-1)2

(n-1)=49

n=50

Sn=n/2(a+an)=25×100

denominator=2+4+6......100

100=2+(n-1)2

n=50

Sn=25×102

hence answer=2500/25×102=100/102=50/51

Please mark as Brainliest.

Answer 2

$\frac{(1 +3 + 5 + 9......... + 99)}{(2 + 4 + 6 + ....... + 100)} \\ = > \frac{(1 + 2 + 3 + 4......100) - (2 + 4 + 6 + ....... + 100)}{(2 + 4 + 6 + ....... + 100)} \\ = > \frac{(1 + 2 + 3 + 4......100)}{(2 + 4 + 6 + ....... + 100)} - 1 \\ = > \frac{(1 + 2 + 3 + 4......100)}{2(1 + 2 + 3 + 4......50)} - 1\\ = > \frac{ \frac{100(101)}{2} }{ \frac{2(50)(51)}{2} } - 1 \\ = > \frac{101}{51} - 1 \\ = > \frac{101 - 51}{51} \\ = > \frac{50}{51}$