Question

1+3+5+........... +99 (find the sums

Answer 1

Step-by-step explanation:

the will be the answer is 7 know whether it is a correct answer

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Answer 2

Answer:

There a formula deviatiom for this section of calculatio.

This is called ARITHMETIC PROFRESSION.

BY AP WE HAVE

A=1 (first term)

AND,D=2 (difference between each term)

An=99 (last term)

Lets first rind that how many terms exist here.

By a.p

An=a+(n-1)d

99=1+(n-1)2

98=(n-1)2

n-1=49

And n=50

There are 50 terms in all…

Now sum of this 50 terms

Sn=n/2(a+An)

S50=25(1+99)

AND,S50=25(100)

WHICH IS * 2500***

Hence the sum of the numbers …..as per question given is 2500.