1+3+5+......to n terms÷2+5+8+...to 8 terms =9, then the value of n is
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- in this case in 1st ap a=1 ,d=2 and in 2nd ap A=2,D=3 ,N=8
- by Sn formula , Sn of 1st ap/Sn of 2nd ap =9
- by putting the formula n/2[2a+(n-1)d] divided by N/2[2A+(N-1)D]=9
- n/2[2+2n-2]divided by 8/2[4+21]=9
- n²/100=9
- n2=900
- n=√900
- n=30
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