1) 3.6gram of a compound containing carbon, hydrogen and oxygen gave on combustion 5.28
gram of carbon dioxide and 2.16gram of water. The molecular mass of the compound was found
to be 60.
a. What are the masses of C, H and O in 3.6 gram of the compound ?
b. What are the empirical and molecular formulas of the compound?
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Answers
Explanation:
\boxed{\rm{\orange{Given \longrightarrow }}}
Given⟶
⇢Points are P(4,3), Q(-5-1), T(2,-2)
\boxed{\rm{\red{To\:Find\longrightarrow }}}
ToFind⟶
⇢whether the given points form a triangle
\boxed{\rm{\pink{solution \longrightarrow }}}
solution⟶
⇢First we find the lengths PQ,QT,PTPQ,QT,PT
PQ=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}PQ=
(x
1
−x
2
)
2
+(y
1
−y
2
)
2
PQ=\sqrt{(4+5)^2+(3+1)^2}PQ=
(4+5)
2
+(3+1)
2
PQ=\sqrt{9^2+4^2}PQ=
9
2
+4
2
PQ=\sqrt{81+16}PQ=
81+16
\bf\,PQ=\sqrt{97}PQ=
97
QT=\sqrt{(-5-2)^2+(-1+2)^2}QT=
(−5−2)
2
+(−1+2)
2
QT=\sqrt{(-7)^2+1^2}QT=
(−7)
2
+1
2
QT=\sqrt{49+1}QT=
49+1
\bf\,QT=\sqrt{50}QT=
50
PT=\sqrt{(4-2)^2+(3+2)^2}PT=
(4−2)
2
+(3+2)
2
PT=\sqrt{2^2+5^2}PT=
2
2
+5
2
PT=\sqrt{4+25}PT=
4+25
\bf\,PT=\sqrt{29}PT=
29
\implies\bf\,PQ{\neq}QT{\neq}PT⟹PQ
=QT
=PT
∴The given points P,Q and T form a scalene triangle
\boxed{\textbf{Option (c) is corrct}}
Option (c) is corrct