1/3*7+1/7*11+1/11*15+.....1/47*51=
Answers
Answered by
20
We have to find the value of 1/3*7+1/7*11+1/11*15+.....1/47*51.
This is a problem of summing a arithmetic progress. At first, we take 1/3*7 which can be expressed by the subtraction of two terms and the terms can be written as
1/3*7 = (7-3)/7*3
= 1/4*3 - 1/4*7
Similarly, 1/7*11 can be written as
1/7*11 = (11-7)/7*11
= 1/7*4 - 1/4*11
Proceeding in this way, we have
1/47*51 = (51-47)/51*47
= 1/4*47 - 1/4*51
Summing all terms we have
1/3*7+1/7*11+1/11*15+.....1/47*51
=(1/4*3 - 1/4*7) + (1/7*4 - 1/4*11) +................ + (1/4*47 - 1/4*51)
=1/4*3 -1/4*51
=4/51
answer: 4/51
Answered by
0
Answer:
The answer is 4/51
Step-by-step explanation:
Explanation in above answer. :) :) :)
Similar questions