Math, asked by arshavanand, 1 year ago

1/3*7+1/7*11+1/11*15+.....1/47*51=

Answers

Answered by retardhero
20

We have to find the value of 1/3*7+1/7*11+1/11*15+.....1/47*51.

This is a problem of summing a arithmetic progress. At first, we take 1/3*7 which can be expressed by the subtraction of two terms and the terms can be written as

1/3*7 = (7-3)/7*3

        = 1/4*3 - 1/4*7

Similarly, 1/7*11 can be written as

1/7*11 = (11-7)/7*11

        = 1/7*4 - 1/4*11

Proceeding in this way, we have

1/47*51 = (51-47)/51*47

            = 1/4*47 - 1/4*51

Summing all terms we have

1/3*7+1/7*11+1/11*15+.....1/47*51

=(1/4*3 - 1/4*7) + (1/7*4 - 1/4*11) +................ + (1/4*47 - 1/4*51)

=1/4*3 -1/4*51

=4/51

answer: 4/51

Answered by dolanchampaparbat
0

Answer:

The answer is 4/51

Step-by-step explanation:

Explanation in above answer. :) :) :)

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