Question

1. 3 A55B 1063 C is a 10 digit number. If it is completely divisible by 792 , find A, B, C ​

Answer 1

Answer:

First we have to break 72 into factors 9,8

Now,

(i) Divisibility Rule of 8 is that the last three digits should be divisible by 8

and

(ii) Divisibility Rule of 9 is that the sum of digits must be divisible by 9

So, 79B must be divisible by 8 and only B=2 is satisfying the condition

Now, using (ii) we get, A+6+7+9+2=9α (multiple of 9)

A=9α−24 only α=3 is satisfying by hit and trial method

So. A=27−24=3

Therefore, A=3,B=2