Question

(1) 3 cm
(11) 5 cm
(1) 12 cm, 10 cm, 5 cm
(iii) 2.5 cm, 2 m, 2.4 m
(ii) 5 cm, 3.5 cm, 1.4 cm
(iv) 8 m, 5 m, 3.5 m
5
required to do so
2. Find the total surface area of the cuboids of length, breadth and height as given be
long. 2.5 cm broad and 1.5 cm in height. Its outer sides are to​

Answer 1

Answer:

(1) length =12 cm breadth =10 cm height =5 cm

TSA=2(lb+bh+lh)=2[12×10+10×5+5×12]

TSA=2[120+50+60]=2×230

[TSA=460cm

2

]

(2) length =5 cm breadth =3.5 cm height =1.4 cm

TSA=2(lb+bh+lh)=2[5×3.5+3.5×14+1.4×5]

TSA=2[17.5+4.90+7.0]=2[29.4]

[TSA=58.8cm

2

]

(3) length =2.5 cm breadth =2 m height =2.4 m

TSA=2(lb+bh+lh)=2[0.025×2+2×2.4+2.4×0.025]

TSA=2[0.05+4.8+0.0600]=2[4.91]

(4) length =8 m breadth =5 m height =3.5 m

TSA=2(lb+bh+lh)=2[8×5+5×3.5+3.5×8]

TSA=2[40+17.5+28.0]=2[85.5]

[TSA=171.0m

2

]