Question

1 - 3 cos²A * sin²A =

a.) cos⁶A + sin⁶A
b.) cos⁶A - sin⁶A
c.) sin⁶A
d.) cos⁶A

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Answer 1

Step-by-step explanation:

LHS = cos^6 A + sin^6 A. = (cos²A)^3 + (sin²A)^3. Using identity (a + b)^3 = a^3 +b^ 3 + 3ab ( a+b). => a^3 +b^3 = ( a+ b)^3 -3ab ( a+ b). So, (cos²A)^3 + ( sin² A)^3.

Hope it helps

Answer 2

Answer:

b) cos⁶A - sin⁶A

Step-by-step explanation:

1 - 3 cos²A * sin²A = cos⁶A - sin⁶A

hope it helps

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