Question

(1
מו
3. Find the area of a triangle, whose perimeter
24cm
and the other 2 Sides are locm.
and 6cm​

Answer 1

Step-by-step explanation:

Preimeter of triangle = A+B+C

24=10+6+C

C=24-16

C=8

SEMI PERIMETER (S)= PERIMETER/2 = 24/2 = 12

$a = \sqrt{s(s - a)(s - b)(s - c)}$

$a = \sqrt{12(12 - 10)(12 - 6)(12 - 8)}$

$a = \sqrt{12 \times 2 \times 6 \times 4}$

$a = \sqrt{576}$

$a = 24$

Hence

Area of Triangle =24m^2

Hope it helps

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