Question

1.3 Find the area of shape.
Menurement given in cm
​

Answer 1

Answer:

(i) Its seen that,

Total area of the figure = Area of trapezium ABCD + Area of rectangle GAFE

Now, Area of trapezium ABCD

=

2

1

× (Sum of parallel sides) × (height)

=

2

1

×(AB+CD)×(AF+FD)

=

2

1

×(5+3)×(5+4)

=

2

1

×8×9=36cm

2

Area of rectangle GAFE=Length×Breadth

=2×5=10cm

2

Hence,

Total area of the figure =36+10 cm

2

=46 cm

2

(ii) Its seen that,

Area of given figure = Area of rect. ABCD + Area of parallelogram BIHJ + Area of rectangle EFGH

Now, Area of rectangle ABCD=Length×Breadth

=AD×CD=9×2=18 cm

2

Area of rectangle EFGH=Length×Breadth

=(EJ+JH)×EF

=(7+2)×2=7×2=18cm

2

Area of parallelogram BIHJ=2×5=10cm

2

(Since distance between BI And HJ=9−2−2=5cm)

Hence

Total area of the figure =(18+18+10)cm

2

=46cm

2

Explanation:

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