Question

1/(3+i)^2 + 1/(3-i)^2 -2i find the conjugate of the complex number​

Answer 1

Step-by-step explanation:

Find the conjugates of the following complex numbers:

(i) (3 – i)2/(2 + i)

(ii) [(1 + i) (2 + i)]/(3 + i)

(iii) [(3 – 2i) (2 + 3i)]/[(1 + 2i) (2 – i)](i) (3 – i)2/(2 + i)

Given as (3 – i)2/(2 + i) Here the given complex number is not in the standard form of (a + ib)

Now let us convert to standard form