Question

1
3
If sin
I=
COSI=
2
--
3
then x
lies in​

Answer 1

Answer:

Since 0<A<90o we know that ∠A is in the first quadrant.

Consider the right △OAB where O is the origin and side AB is opposite ∠A

We are told that sinA=13

∴ side AB=1 and side OA=3

Applying Pythagoras

(OA)2=(AB)2+(OB)2

∴32=12+OB2

OB=√9−1 [Since OB>0 because ∠A is in the first quadrant]

OB=√8=2√2

Now, cosA=OBOA

cosA=2√23

Step-by-step explanation:

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