1.3 In the given series of reactions, Y and Z respectively are : A +10H2O NaCl + H2O + CO2 + NH3 - X+Y → Z - H20,- CO2 Q (Q is used in removing permanent hardness of water). (a) NaHCO3, NaOCl2 (c) Na2CO, NHẠC (b) NH,CI, Na Coz (d) Na, CO3, NaHCO,
Answers
Answered by
1
Answer:
NH
4HCO3,NaHCO3
Explanation:
NH4
HHCO,NaHCO
3
Ammonium chloride reacts with sodium hydroxide to form sodium chloride, ammonia and water.
NH
4
Cl+NaOH
Heat
NaCl+NH
3
+H
2
O
(A)
Ammonia reacts with carbon dioxide and water to form ammonium bicarbonate.
NH
3
+CO
2
+H
2
O
NH
4
HCO
3
(B)
Ammonium carbonate reacts with sodium chloride to form sodium bicarbonate and ammonium chloride.
NH
4
HCO
3
+NaCl
NaHCO
3
+NH
4
Cl
(B)(C)
Sodium bicarbonate decomposes to give sodium carbonate, water and carbon dioxide.
2NaHCO
3
Na
2
CO
3
+H
2
O+CO
2
(C)(D)
Answered by
1
Explanation:
1.3 in the given series of reaction Y and Z so the answer is (c)and (D)
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