Question

1/3(n+1)+2=1/6(3n-5) solve for n

Answer 1

2(3n-5)+2*18(n+1)(3n-5)=(n+1)
36(3n^2-2n-5)=n+1-6n+10
36(3n^2-2n-5)=-5n+11
108n^2+78n+5n-180-11=0
108n^2+83n-191=0
(n-1)(108n+191)=0
n=-191/108,1

Answer 2

1/3(n+1)+2=1/6(3n-5)
1n/3+1/3+2=1n/2-5/6
1n/3-1n/2=-5/6-1/3-2
2n-3n/6=-15-2-12/6
-n/6=-29/6
n=29*6/6
n=29