1÷3 of (6+8×1)+(1÷5 ÷ 7÷25 - (3÷7+8÷14))
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0
Answer:
According to the BODMAS rule
1÷3 of (6+8×1)+(1÷5 ÷ 7÷25 - (3÷7+8÷14))
=3(6+8×1)+(1÷5÷7÷25-(3÷7+8÷14)
=3(6+8)+(5÷7÷25-(10÷14)
=3+14+(1÷7÷25-1
=17+(7÷25-1)
=17+2
=19
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Answered by
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Step-by-step explanation:
((1/3) *(6+(8*1))) +((((1/5)/7) /2= 3.66780952381
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