1/3 p + 2 When p = 6
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Step-by-step explanation:
his can be best visualised through the use of a Venn diagram.
Since A and B are independent, P(A|B)=P(A)
Therefore, P(A)=P(A intersection B)/P(B)
Therefore P(A intersection B)=P(A)P(B)=1/6
Imagine a Venn Diagram with 2 overlapping circles. The union of these 2 circles is equivalent to adding up the 2 circles individually and then subtracting the common bit.
P(A union B)=P(A)+P(B)−P(A intersection B)
P(A union B)=1/2+1/3−1/6=2/3=0.666...
And there you have it.
hope it helps u
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