Question

(1/3) power 5 divide (1/3) multiple (1/3)power -4​

Answer 1

Answer:

$( \frac{1}{3})^{3} \div \frac{1}{3} \times ( \frac{1}{3}) {}^{ - 4} \\ \frac{1}{243} \div \frac{1}{3} \times 81 \\ \frac{1}{243} \times \frac{3}{1} \times 81 \\ \frac{1}{81} \times 81 \\ 1 \: ans$

Answer 2

Answer:

$(1/3)^{8}$

Step-by-step explanation:

($(1/3)^{5}$ )  /  (   $(1/3)$  *   $(1/3)^{-4}$  )

Step-1 :-  fist we will solve the denominator by using the following property

$a^{b}$ * $a^{c}$  =  $(a)^{b+c}$  and we will get $(1/3)^{1-4}$

(  $(1/3)^{-5}$  )  /  (  $(1/3)^{-3}$ )      ..... eq(1)

Step-2 :- By using the following property we will rewrite the equation 1

$(1/a)^{-b}$ = $a^{b}$  . When we reciprocal the with negative power that number power become positive

(  $(1/3)^{5}$ * $(1/3)^{3}$ )

Step-3 :-  In this step we will again use the property which has been defined in the first step

(  $(1/3)^{5+3}$ )     =  $(1/3)^{8}$