Question

1/3 power-7+9/27power-3​

Answer 1

Answer:

$\left(\frac{1}{3}\right)^{-7}+\left(\frac{9}{27}\right)^{-3}=2214$

Step-by-step explanation:

$\left(\frac{1}{3}\right)^{-7}+\left(\frac{9}{27}\right)^{-3}\\=\left(\frac{1}{3}\right)^{-7}+\left(\frac{1}{3}\right)^{-3}\\=3^{7}+3^{3}\\=3^{3}(3^4+1)\\=27(81+1)\\=27\times 82\\=2214$

Therefore,

$\left(\frac{1}{3}\right)^{-7}+\left(\frac{9}{27}\right)^{-3}=2214$

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Answer 2

2214

Step-by-step explanation:

Given:

$(\frac{1}{3}$$)^{-7}$ +  $(\frac{9}{27}$$)^{-3}$

To convert negative exponent to positive, the numerator and denominator are interchanged:

$(\frac{3}{1}$$)^{7}$ +  $(\frac{27}{9}$$)^{3}$

Dividing 27 by 9:

(3)⁷ + (3)³

3⁷ + 3³

(3 × 3 × 3 × 3 × 3 × 3 × 3) + (3 × 3 × 3)

2187 + 27

2214

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