Question

1,3 question answers​

Answer 1

$HEYA \\ \\ \: QUESTION \: No \: \: 1 \ \\ \\ \sqrt[5]{(243) {}^{2} } \\ \\ \sqrt[5]{(3 {}^{5}) {}^{2} } \\ becoz \: \: 243 = 3 {}^{5} \\ \\ \sqrt[5]{(3) {}^{10} } \\ \\ 3 {}^{(10) \div 5} \\ \\ 3 {}^{2} \\ \\ = 9 \\ \\ \\ QUESTION \: \: No \: \: \: \: \: 2 \\ \\ 2 {}^{x} + 2 {}^{x + 1} = 24 \\ \\ 2 {}^{x} + 2 {}^{x} \times 2 {}^{1} = 24 \\ \\ 2 {}^{x} (1 + 2) = 24 \\ \\ 2 {}^{x} \times (3) = 24 \\ \\ 2 {}^{x} = 24 \div 3 \\ \\ 2 {}^{x} = 8 \\ \\ 2 {}^{x} = 2 {}^{3} \\ becoz \: \: \: \: 8 = 2 {}^{3} \\ now \: compare \: powers \: of \: 2 \: \: we \: have \\ \\ x = 3 \\ \\ therefore \: \: \: \: x = 3$

Answer 2

Step-by-step explanation:

$\begin{lgathered}Question \: No \: \: 1 \ \\ \\ \sqrt[5]{(243) {}^{2} } \\ \\ \sqrt[5]{(3 {}^{5}) {}^{2} } \\ Because \: \: 243 = 3 {}^{5} \\ \\ \sqrt[5]{(3) {}^{10} } \\ \\ 3 {}^{(10) \div 5} \\ \\ 3 {}^{2} \\ \\ = 9 \\ \\ \\ Question \: \: No \: \: \: \: \: 2 \\ \\ 2 {}^{x} + 2 {}^{x + 1} = 24 \\ \\ 2 {}^{x} + 2 {}^{x} \times 2 {}^{1} = 24 \\ \\ 2 {}^{x} (1 + 2) = 24 \\ \\ 2 {}^{x} \times (3) = 24 \\ \\ 2 {}^{x} = 24 \div 3 \\ \\ 2 {}^{x} = 8 \\ \\ 2 {}^{x} = 2 {}^{3} \\ Because \: \: \: \: 8 = 2 {}^{3} \\ Now \: Compare \: Powers \: of \: 2 \: \: We \: Have \\ \\ x = 3 \\ \\ Therefore \: \: \: \: x = 3\end{lgathered}$